7(4p^2)=4

Solution for 7(4p^2)=4 equation:

7(4p^2)=4

We move all terms to the left:

7(4p^2)-(4)=0

a = 74; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·74·(-4)
Δ = 1184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1184}=\sqrt{16*74}=\sqrt{16}*\sqrt{74}=4\sqrt{74}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{74}}{2*74}=\frac{0-4\sqrt{74}}{148}
=-\frac{4\sqrt{74}}{148}
=-\frac{\sqrt{74}}{37}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{74}}{2*74}=\frac{0+4\sqrt{74}}{148}
=\frac{4\sqrt{74}}{148}
=\frac{\sqrt{74}}{37}
$